Ecuación diferencial (1-x)(y'+y)=e^(-x)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
-x
y(x) = (C1 - log(-1 + x))*e
$$y{\left(x \right)} = \left(C_{1} - \log{\left(x - 1 \right)}\right) e^{- x}$$
Clasificación
factorable
1st exact
1st linear
Bernoulli
almost linear
1st power series
lie group
1st exact Integral
1st linear Integral
Bernoulli Integral
almost linear Integral