(sqrt(1-2*x))*(ln(16*(x*x)-(a*a)))=(sqrt(1-2*x))*(ln(4*x+a)) la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
$$x_{1} = \frac{1}{2}$$
1 re(a) I*im(a)
x2 = - + ----- + -------
4 4 4
$$x_{2} = \frac{\operatorname{re}{\left(a\right)}}{4} + \frac{i \operatorname{im}{\left(a\right)}}{4} + \frac{1}{4}$$
x2 = re(a)/4 + i*im(a)/4 + 1/4
Suma y producto de raíces
[src]
1 1 re(a) I*im(a)
- + - + ----- + -------
2 4 4 4
$$\left(\frac{\operatorname{re}{\left(a\right)}}{4} + \frac{i \operatorname{im}{\left(a\right)}}{4} + \frac{1}{4}\right) + \frac{1}{2}$$
3 re(a) I*im(a)
- + ----- + -------
4 4 4
$$\frac{\operatorname{re}{\left(a\right)}}{4} + \frac{i \operatorname{im}{\left(a\right)}}{4} + \frac{3}{4}$$
1 re(a) I*im(a)
- + ----- + -------
4 4 4
-------------------
2
$$\frac{\frac{\operatorname{re}{\left(a\right)}}{4} + \frac{i \operatorname{im}{\left(a\right)}}{4} + \frac{1}{4}}{2}$$
1 re(a) I*im(a)
- + ----- + -------
8 8 8
$$\frac{\operatorname{re}{\left(a\right)}}{8} + \frac{i \operatorname{im}{\left(a\right)}}{8} + \frac{1}{8}$$
1/8 + re(a)/8 + i*im(a)/8