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log(2*y+1)/2=c+log(sin(x)) la ecuación

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Solución numérica:

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Solución

Ha introducido [src] 
log(2*y + 1)                  
------------ = c + log(sin(x))
     2
log⁡(2y+1)2=c+log⁡(sin⁡(x))\frac{\log{\left(2 y + 1 \right)}}{2} = c + \log{\left(\sin{\left(x \right)} \right)}
Simplificar
Gráfica
Suma y producto de raíces [src] 
suma
       /    /  _________  -c\\       /    /  _________  -c\\       /    /  _________  -c\\     /    /  _________  -c\\
pi - re\asin\\/ 1 + 2*y *e  // - I*im\asin\\/ 1 + 2*y *e  // + I*im\asin\\/ 1 + 2*y *e  // + re\asin\\/ 1 + 2*y *e  //
(re⁡(asin⁡(2y+1e−c))+iim⁡(asin⁡(2y+1e−c)))+(−re⁡(asin⁡(2y+1e−c))−iim⁡(asin⁡(2y+1e−c))+π)\left(\operatorname{re}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)}\right) + \left(- \operatorname{re}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} - i \operatorname{im}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} + \pi\right) 
=
pi
π\pi 
producto
/       /    /  _________  -c\\       /    /  _________  -c\\\ /    /    /  _________  -c\\     /    /  _________  -c\\\
\pi - re\asin\\/ 1 + 2*y *e  // - I*im\asin\\/ 1 + 2*y *e  ///*\I*im\asin\\/ 1 + 2*y *e  // + re\asin\\/ 1 + 2*y *e  ///
(re⁡(asin⁡(2y+1e−c))+iim⁡(asin⁡(2y+1e−c)))(−re⁡(asin⁡(2y+1e−c))−iim⁡(asin⁡(2y+1e−c))+π)\left(\operatorname{re}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)}\right) \left(- \operatorname{re}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} - i \operatorname{im}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} + \pi\right) 
=
 /    /    /  _________  -c\\     /    /  _________  -c\\\ /          /    /  _________  -c\\     /    /  _________  -c\\\
-\I*im\asin\\/ 1 + 2*y *e  // + re\asin\\/ 1 + 2*y *e  ///*\-pi + I*im\asin\\/ 1 + 2*y *e  // + re\asin\\/ 1 + 2*y *e  ///
−(re⁡(asin⁡(2y+1e−c))+iim⁡(asin⁡(2y+1e−c)))(re⁡(asin⁡(2y+1e−c))+iim⁡(asin⁡(2y+1e−c))−π)- \left(\operatorname{re}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)}\right) \left(\operatorname{re}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} - \pi\right) 
-(i*im(asin(sqrt(1 + 2*y)*exp(-c))) + re(asin(sqrt(1 + 2*y)*exp(-c))))*(-pi + i*im(asin(sqrt(1 + 2*y)*exp(-c))) + re(asin(sqrt(1 + 2*y)*exp(-c))))
Respuesta rápida [src] 
            /    /  _________  -c\\       /    /  _________  -c\\
x1 = pi - re\asin\\/ 1 + 2*y *e  // - I*im\asin\\/ 1 + 2*y *e  //
x1=−re⁡(asin⁡(2y+1e−c))−iim⁡(asin⁡(2y+1e−c))+πx_{1} = - \operatorname{re}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} - i \operatorname{im}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} + \pi 
         /    /  _________  -c\\     /    /  _________  -c\\
x2 = I*im\asin\\/ 1 + 2*y *e  // + re\asin\\/ 1 + 2*y *e  //
x2=re⁡(asin⁡(2y+1e−c))+iim⁡(asin⁡(2y+1e−c))x_{2} = \operatorname{re}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(\sqrt{2 y + 1} e^{- c} \right)}\right)} 
x2 = re(asin(sqrt(2*y + 1)*exp(-c))) + i*im(asin(sqrt(2*y + 1)*exp(-c)))
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