log(x+a)+(x+b)*5=0 la ecuación
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Solución
/ / -5*b + 5*a\\ / / / -5*b + 5*a\\\
re\W\5*e // | im\W\5*e //|
x1 = -re(a) + -------------------- + I*|-im(a) + --------------------|
5 \ 5 /
$$x_{1} = i \left(- \operatorname{im}{\left(a\right)} + \frac{\operatorname{im}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}\right) - \operatorname{re}{\left(a\right)} + \frac{\operatorname{re}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}$$
x1 = i*(-im(a) + im(LambertW(5*exp(5*a - 5*b)))/5) - re(a) + re(LambertW(5*exp(5*a - 5*b)))/5
Suma y producto de raíces
[src]
/ / -5*b + 5*a\\ / / / -5*b + 5*a\\\
re\W\5*e // | im\W\5*e //|
-re(a) + -------------------- + I*|-im(a) + --------------------|
5 \ 5 /
$$i \left(- \operatorname{im}{\left(a\right)} + \frac{\operatorname{im}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}\right) - \operatorname{re}{\left(a\right)} + \frac{\operatorname{re}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}$$
/ / -5*b + 5*a\\ / / / -5*b + 5*a\\\
re\W\5*e // | im\W\5*e //|
-re(a) + -------------------- + I*|-im(a) + --------------------|
5 \ 5 /
$$i \left(- \operatorname{im}{\left(a\right)} + \frac{\operatorname{im}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}\right) - \operatorname{re}{\left(a\right)} + \frac{\operatorname{re}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}$$
/ / -5*b + 5*a\\ / / / -5*b + 5*a\\\
re\W\5*e // | im\W\5*e //|
-re(a) + -------------------- + I*|-im(a) + --------------------|
5 \ 5 /
$$i \left(- \operatorname{im}{\left(a\right)} + \frac{\operatorname{im}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}\right) - \operatorname{re}{\left(a\right)} + \frac{\operatorname{re}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}$$
/ / -5*b + 5*a\\ / / / -5*b + 5*a\\\
re\W\5*e // | im\W\5*e //|
-re(a) + -------------------- + I*|-im(a) + --------------------|
5 \ 5 /
$$i \left(- \operatorname{im}{\left(a\right)} + \frac{\operatorname{im}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}\right) - \operatorname{re}{\left(a\right)} + \frac{\operatorname{re}{\left(W\left(5 e^{5 a - 5 b}\right)\right)}}{5}$$
-re(a) + re(LambertW(5*exp(-5*b + 5*a)))/5 + i*(-im(a) + im(LambertW(5*exp(-5*b + 5*a)))/5)