log(b)-log(a)=y la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
y1 = -log(|a|) + I*(-arg(a) + arg(b)) + log(|b|)
$$y_{1} = i \left(- \arg{\left(a \right)} + \arg{\left(b \right)}\right) - \log{\left(\left|{a}\right| \right)} + \log{\left(\left|{b}\right| \right)}$$
y1 = i*(-arg(a) + arg(b)) - log(|a|) + log(|b|)
Suma y producto de raíces
[src]
-log(|a|) + I*(-arg(a) + arg(b)) + log(|b|)
$$i \left(- \arg{\left(a \right)} + \arg{\left(b \right)}\right) - \log{\left(\left|{a}\right| \right)} + \log{\left(\left|{b}\right| \right)}$$
-log(|a|) + I*(-arg(a) + arg(b)) + log(|b|)
$$i \left(- \arg{\left(a \right)} + \arg{\left(b \right)}\right) - \log{\left(\left|{a}\right| \right)} + \log{\left(\left|{b}\right| \right)}$$
-log(|a|) + I*(-arg(a) + arg(b)) + log(|b|)
$$i \left(- \arg{\left(a \right)} + \arg{\left(b \right)}\right) - \log{\left(\left|{a}\right| \right)} + \log{\left(\left|{b}\right| \right)}$$
-log(|a|) + I*(-arg(a) + arg(b)) + log(|b|)
$$i \left(- \arg{\left(a \right)} + \arg{\left(b \right)}\right) - \log{\left(\left|{a}\right| \right)} + \log{\left(\left|{b}\right| \right)}$$
-log(|a|) + i*(-arg(a) + arg(b)) + log(|b|)