lnx=C la ecuación

El profesor se sorprenderá mucho al ver tu solución correcta😉

Ha introducido [src]

log(x) = c

\log{\left(x \right)} = c

Simplificar

Solución detallada

Tenemos la ecuación

\log{\left(x \right)} = c

\log{\left(x \right)} = c

Es la ecuación de la forma:

log(v)=p

Por definición log

v=e^p

entonces

x = e^{\frac{c}{1}}

simplificamos

x = e^{c}

Gráfica

Respuesta rápida [src]

                 re(c)      re(c)           
x1 = cos(im(c))*e      + I*e     *sin(im(c))

x_{1} = i e^{\operatorname{re}{\left(c\right)}} \sin{\left(\operatorname{im}{\left(c\right)} \right)} + e^{\operatorname{re}{\left(c\right)}} \cos{\left(\operatorname{im}{\left(c\right)} \right)}

x1 = i*exp(re(c))*sin(im(c)) + exp(re(c))*cos(im(c))

Suma y producto de raíces [src]

suma

            re(c)      re(c)           
cos(im(c))*e      + I*e     *sin(im(c))

i e^{\operatorname{re}{\left(c\right)}} \sin{\left(\operatorname{im}{\left(c\right)} \right)} + e^{\operatorname{re}{\left(c\right)}} \cos{\left(\operatorname{im}{\left(c\right)} \right)}

            re(c)      re(c)           
cos(im(c))*e      + I*e     *sin(im(c))

i e^{\operatorname{re}{\left(c\right)}} \sin{\left(\operatorname{im}{\left(c\right)} \right)} + e^{\operatorname{re}{\left(c\right)}} \cos{\left(\operatorname{im}{\left(c\right)} \right)}

producto

            re(c)      re(c)           
cos(im(c))*e      + I*e     *sin(im(c))

i e^{\operatorname{re}{\left(c\right)}} \sin{\left(\operatorname{im}{\left(c\right)} \right)} + e^{\operatorname{re}{\left(c\right)}} \cos{\left(\operatorname{im}{\left(c\right)} \right)}

 I*im(c) + re(c)
e

e^{\operatorname{re}{\left(c\right)} + i \operatorname{im}{\left(c\right)}}

exp(i*im(c) + re(c))