lnx=C la ecuación
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Solución
Solución detallada
Tenemos la ecuación
$$\log{\left(x \right)} = c$$
$$\log{\left(x \right)} = c$$
Es la ecuación de la forma:
log(v)=p
Por definición log
v=e^p
entonces
$$x = e^{\frac{c}{1}}$$
simplificamos
$$x = e^{c}$$
re(c) re(c)
x1 = cos(im(c))*e + I*e *sin(im(c))
$$x_{1} = i e^{\operatorname{re}{\left(c\right)}} \sin{\left(\operatorname{im}{\left(c\right)} \right)} + e^{\operatorname{re}{\left(c\right)}} \cos{\left(\operatorname{im}{\left(c\right)} \right)}$$
x1 = i*exp(re(c))*sin(im(c)) + exp(re(c))*cos(im(c))
Suma y producto de raíces
[src]
re(c) re(c)
cos(im(c))*e + I*e *sin(im(c))
$$i e^{\operatorname{re}{\left(c\right)}} \sin{\left(\operatorname{im}{\left(c\right)} \right)} + e^{\operatorname{re}{\left(c\right)}} \cos{\left(\operatorname{im}{\left(c\right)} \right)}$$
re(c) re(c)
cos(im(c))*e + I*e *sin(im(c))
$$i e^{\operatorname{re}{\left(c\right)}} \sin{\left(\operatorname{im}{\left(c\right)} \right)} + e^{\operatorname{re}{\left(c\right)}} \cos{\left(\operatorname{im}{\left(c\right)} \right)}$$
re(c) re(c)
cos(im(c))*e + I*e *sin(im(c))
$$i e^{\operatorname{re}{\left(c\right)}} \sin{\left(\operatorname{im}{\left(c\right)} \right)} + e^{\operatorname{re}{\left(c\right)}} \cos{\left(\operatorname{im}{\left(c\right)} \right)}$$
$$e^{\operatorname{re}{\left(c\right)} + i \operatorname{im}{\left(c\right)}}$$