log(x^2-a)/log(2)=1 la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
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4 / 2 2 /atan2(im(a), 2 + re(a))\ 4 / 2 2 /atan2(im(a), 2 + re(a))\
x1 = - \/ (2 + re(a)) + im (a) *cos|-----------------------| - I*\/ (2 + re(a)) + im (a) *sin|-----------------------|
\ 2 / \ 2 /
x1=−i4(re(a)+2)2+(im(a))2sin(2atan2(im(a),re(a)+2))−4(re(a)+2)2+(im(a))2cos(2atan2(im(a),re(a)+2))
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4 / 2 2 /atan2(im(a), 2 + re(a))\ 4 / 2 2 /atan2(im(a), 2 + re(a))\
x2 = \/ (2 + re(a)) + im (a) *cos|-----------------------| + I*\/ (2 + re(a)) + im (a) *sin|-----------------------|
\ 2 / \ 2 /
x2=i4(re(a)+2)2+(im(a))2sin(2atan2(im(a),re(a)+2))+4(re(a)+2)2+(im(a))2cos(2atan2(im(a),re(a)+2))
x2 = i*((re(a) + 2)^2 + im(a)^2)^(1/4)*sin(atan2(im(a, re(a) + 2)/2) + ((re(a) + 2)^2 + im(a)^2)^(1/4)*cos(atan2(im(a), re(a) + 2)/2))
Suma y producto de raíces
[src]
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4 / 2 2 /atan2(im(a), 2 + re(a))\ 4 / 2 2 /atan2(im(a), 2 + re(a))\ 4 / 2 2 /atan2(im(a), 2 + re(a))\ 4 / 2 2 /atan2(im(a), 2 + re(a))\
- \/ (2 + re(a)) + im (a) *cos|-----------------------| - I*\/ (2 + re(a)) + im (a) *sin|-----------------------| + \/ (2 + re(a)) + im (a) *cos|-----------------------| + I*\/ (2 + re(a)) + im (a) *sin|-----------------------|
\ 2 / \ 2 / \ 2 / \ 2 /
(−i4(re(a)+2)2+(im(a))2sin(2atan2(im(a),re(a)+2))−4(re(a)+2)2+(im(a))2cos(2atan2(im(a),re(a)+2)))+(i4(re(a)+2)2+(im(a))2sin(2atan2(im(a),re(a)+2))+4(re(a)+2)2+(im(a))2cos(2atan2(im(a),re(a)+2)))
/ _______________________ _______________________ \ / _______________________ _______________________ \
| 4 / 2 2 /atan2(im(a), 2 + re(a))\ 4 / 2 2 /atan2(im(a), 2 + re(a))\| |4 / 2 2 /atan2(im(a), 2 + re(a))\ 4 / 2 2 /atan2(im(a), 2 + re(a))\|
|- \/ (2 + re(a)) + im (a) *cos|-----------------------| - I*\/ (2 + re(a)) + im (a) *sin|-----------------------||*|\/ (2 + re(a)) + im (a) *cos|-----------------------| + I*\/ (2 + re(a)) + im (a) *sin|-----------------------||
\ \ 2 / \ 2 // \ \ 2 / \ 2 //
(−i4(re(a)+2)2+(im(a))2sin(2atan2(im(a),re(a)+2))−4(re(a)+2)2+(im(a))2cos(2atan2(im(a),re(a)+2)))(i4(re(a)+2)2+(im(a))2sin(2atan2(im(a),re(a)+2))+4(re(a)+2)2+(im(a))2cos(2atan2(im(a),re(a)+2)))
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/ 2 2 I*atan2(im(a), 2 + re(a))
-\/ (2 + re(a)) + im (a) *e
−(re(a)+2)2+(im(a))2eiatan2(im(a),re(a)+2)
-sqrt((2 + re(a))^2 + im(a)^2)*exp(i*atan2(im(a), 2 + re(a)))