Sr Examen

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log(x+y)-log(x-y)=1 la ecuación

El profesor se sorprenderá mucho al ver tu solución correcta😉

Ha introducido [src]

log(x + y) - log(x - y) = 1

- \log{\left(x - y \right)} + \log{\left(x + y \right)} = 1

Simplificar

Gráfica

Suma y producto de raíces [src]

suma

(1 + E)*re(y)   I*(1 + E)*im(y)
------------- + ---------------
    -1 + E           -1 + E

\frac{\left(1 + e\right) \operatorname{re}{\left(y\right)}}{-1 + e} + \frac{i \left(1 + e\right) \operatorname{im}{\left(y\right)}}{-1 + e}

(1 + E)*re(y)   I*(1 + E)*im(y)
------------- + ---------------
    -1 + E           -1 + E

\frac{\left(1 + e\right) \operatorname{re}{\left(y\right)}}{-1 + e} + \frac{i \left(1 + e\right) \operatorname{im}{\left(y\right)}}{-1 + e}

producto

(1 + E)*re(y)   I*(1 + E)*im(y)
------------- + ---------------
    -1 + E           -1 + E

\frac{\left(1 + e\right) \operatorname{re}{\left(y\right)}}{-1 + e} + \frac{i \left(1 + e\right) \operatorname{im}{\left(y\right)}}{-1 + e}

-(1 + E)*(I*im(y) + re(y)) 
---------------------------
           1 - E

- \frac{\left(1 + e\right) \left(\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)}\right)}{1 - e}

-(1 + E)*(i*im(y) + re(y))/(1 - E)

Respuesta rápida [src]

     (1 + E)*re(y)   I*(1 + E)*im(y)
x1 = ------------- + ---------------
         -1 + E           -1 + E

x_{1} = \frac{\left(1 + e\right) \operatorname{re}{\left(y\right)}}{-1 + e} + \frac{i \left(1 + e\right) \operatorname{im}{\left(y\right)}}{-1 + e}

x1 = (1 + E)*re(y)/(-1 + E) + i*(1 + E)*im(y)/(-1 + E)