y=ax-3ax+5a la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
Tenemos una ecuación lineal:
y = a*x-3*a*x+5*a
Obtenemos la respuesta: y = a*(5 - 2*x)
y1 = I*((5 - 2*re(x))*im(a) - 2*im(x)*re(a)) + (5 - 2*re(x))*re(a) + 2*im(a)*im(x)
y1=(5−2re(x))re(a)+i((5−2re(x))im(a)−2re(a)im(x))+2im(a)im(x)
y1 = (5 - 2*re(x))*re(a) + i*((5 - 2*re(x))*im(a) - 2*re(a)*im(x)) + 2*im(a)*im(x)
Suma y producto de raíces
[src]
I*((5 - 2*re(x))*im(a) - 2*im(x)*re(a)) + (5 - 2*re(x))*re(a) + 2*im(a)*im(x)
(5−2re(x))re(a)+i((5−2re(x))im(a)−2re(a)im(x))+2im(a)im(x)
I*((5 - 2*re(x))*im(a) - 2*im(x)*re(a)) + (5 - 2*re(x))*re(a) + 2*im(a)*im(x)
(5−2re(x))re(a)+i((5−2re(x))im(a)−2re(a)im(x))+2im(a)im(x)
I*((5 - 2*re(x))*im(a) - 2*im(x)*re(a)) + (5 - 2*re(x))*re(a) + 2*im(a)*im(x)
(5−2re(x))re(a)+i((5−2re(x))im(a)−2re(a)im(x))+2im(a)im(x)
-I*((-5 + 2*re(x))*im(a) + 2*im(x)*re(a)) - (-5 + 2*re(x))*re(a) + 2*im(a)*im(x)
−i((2re(x)−5)im(a)+2re(a)im(x))−(2re(x)−5)re(a)+2im(a)im(x)
-i*((-5 + 2*re(x))*im(a) + 2*im(x)*re(a)) - (-5 + 2*re(x))*re(a) + 2*im(a)*im(x)