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(x^2-5x+3)/(x-4)+(5x-27)/(x-6)<=x+4
Resolver desigualdades/ (x^2-5x+3)/(x-4)+(5x-27)/(x-6)<=x+4

(x^2-5x+3)/(x-4)+(5x-27)/(x-6)<=x+4 desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src] 
 2                              
x  - 5*x + 3   5*x - 27         
------------ + -------- <= x + 4
   x - 4        x - 6
$$\frac{\left(x^{2} - 5 x\right) + 3}{x - 4} + \frac{5 x - 27}{x - 6} \leq x + 4$$ 
(x^2 - 5*x + 3)/(x - 4) + (5*x - 27)/(x - 6) <= x + 4
Solución de la desigualdad en el gráfico
Respuesta rápida [src] 
Or(And(x <= 3, -oo < x), And(4 < x, x < 6))
$$\left(x \leq 3 \wedge -\infty < x\right) \vee \left(4 < x \wedge x < 6\right)$$ 
((x <= 3)∧(-oo < x))∨((4 < x)∧(x < 6))
Respuesta rápida 2 [src] 
(-oo, 3] U (4, 6)
$$x\ in\ \left(-\infty, 3\right] \cup \left(4, 6\right)$$ 
x in Union(Interval(-oo, 3), Interval.open(4, 6))
Gráfico
(x^2-5x+3)/(x-4)+(5x-27)/(x-6)<=x+4 desigualdades
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