| 2 | |x + 5| > |2*x + 3| - 8
|x + 5| > |2*x^2 + 3| - 8
(-2, 5/2)
x in Interval.open(-2, 5/2)
And(-2 < x, x < 5/2)
(-2 < x)∧(x < 5/2)