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log0,2(6-x)<=log0,2(x+1) desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
log(0.0)*2*(6 - x) <= log(0.0)*2*(x + 1)
$$2 \log{\left(0.0 \right)} \left(6 - x\right) \leq 2 \log{\left(0.0 \right)} \left(x + 1\right)$$
(2*log(0.0))*(6 - x) <= (2*log(0.0))*(x + 1)