log(3) log(3) ------*(4*x - 7) < ------*(x + 2) 4 4
(log(3)/4)*(4*x - 7) < (log(3)/4)*(x + 2)
And(-oo < x, x < 3)
(-oo < x)∧(x < 3)
(-oo, 3)
x in Interval.open(-oo, 3)