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(log2*x+1(4*x-5))+(log4*x-5(2*x+1))<=2 desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
log(2*x) + 4*x - 5 + log(4*x) - 5*(2*x + 1) <= 2
$$\left(- 5 \left(2 x + 1\right) + \log{\left(4 x \right)}\right) + \left(\left(4 x - 5\right) + \log{\left(2 x \right)}\right) \leq 2$$
-5*(2*x + 1) + log(4*x) + 4*x - 5 + log(2*x) <= 2