4*(x + 2) x - 10 x + --------- < 2*x - ------ 2 5
x + (4*(x + 2))/2 < 2*x - (x - 10)/5
And(-oo < x, x < -5/3)
(-oo < x)∧(x < -5/3)
(-oo, -5/3)
x in Interval.open(-oo, -5/3)