|x|*log(1) ----------*(x + 1/3) + x < 0 2
x + ((log(1)*|x|)/2)*(x + 1/3) < 0
And(-oo < x, x < 0)
(-oo < x)∧(x < 0)
(-oo, 0)
x in Interval.open(-oo, 0)