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Integral de 1/(√(x+1)^1/3)+(√(x+1)) dx

Límites de integración:

interior superior
v

Gráfico:

interior superior

Definida a trozos:

Solución

Ha introducido [src]
  1                                
  /                                
 |                                 
 |  /      1            _______\   
 |  |-------------- + \/ x + 1 | dx
 |  |   ___________            |   
 |  |3 /   _______             |   
 |  \\/  \/ x + 1              /   
 |                                 
/                                  
0                                  
01(x+1+1x+13)dx\int\limits_{0}^{1} \left(\sqrt{x + 1} + \frac{1}{\sqrt[3]{\sqrt{x + 1}}}\right)\, dx
Integral(1/((sqrt(x + 1))^(1/3)) + sqrt(x + 1), (x, 0, 1))
Solución detallada
  1. Integramos término a término:

    1. que u=x+1u = x + 1.

      Luego que du=dxdu = dx y ponemos dudu:

      udu\int \sqrt{u}\, du

      1. Integral unu^{n} es un+1n+1\frac{u^{n + 1}}{n + 1} when n1n \neq -1:

        udu=2u323\int \sqrt{u}\, du = \frac{2 u^{\frac{3}{2}}}{3}

      Si ahora sustituir uu más en:

      2(x+1)323\frac{2 \left(x + 1\right)^{\frac{3}{2}}}{3}

    1. No puedo encontrar los pasos en la búsqueda de esta integral.

      Pero la integral

      {(x+1)56Γ(56)Γ(116)forx+1>0G2,21,1(1116560|x+1)+G2,20,2(116,156,0|x+1)otherwese\begin{cases} \frac{\left(x + 1\right)^{\frac{5}{6}} \Gamma\left(\frac{5}{6}\right)}{\Gamma\left(\frac{11}{6}\right)} & \text{for}\: \left|{x + 1}\right| > 0 \\{G_{2, 2}^{1, 1}\left(\begin{matrix} 1 & \frac{11}{6} \\\frac{5}{6} & 0 \end{matrix} \middle| {x + 1} \right)} + {G_{2, 2}^{0, 2}\left(\begin{matrix} \frac{11}{6}, 1 & \\ & \frac{5}{6}, 0 \end{matrix} \middle| {x + 1} \right)} & \text{otherwese} \end{cases}

    El resultado es: 2(x+1)323+{(x+1)56Γ(56)Γ(116)forx+1>0G2,21,1(1116560|x+1)+G2,20,2(116,156,0|x+1)otherwese\frac{2 \left(x + 1\right)^{\frac{3}{2}}}{3} + \begin{cases} \frac{\left(x + 1\right)^{\frac{5}{6}} \Gamma\left(\frac{5}{6}\right)}{\Gamma\left(\frac{11}{6}\right)} & \text{for}\: \left|{x + 1}\right| > 0 \\{G_{2, 2}^{1, 1}\left(\begin{matrix} 1 & \frac{11}{6} \\\frac{5}{6} & 0 \end{matrix} \middle| {x + 1} \right)} + {G_{2, 2}^{0, 2}\left(\begin{matrix} \frac{11}{6}, 1 & \\ & \frac{5}{6}, 0 \end{matrix} \middle| {x + 1} \right)} & \text{otherwese} \end{cases}

  2. Ahora simplificar:

    {2(9(x+1)56+5(x+1)32)15forx+1>02(x+1)323+G2,21,1(1116560|x+1)+G2,20,2(116,156,0|x+1)otherwese\begin{cases} \frac{2 \left(9 \left(x + 1\right)^{\frac{5}{6}} + 5 \left(x + 1\right)^{\frac{3}{2}}\right)}{15} & \text{for}\: \left|{x + 1}\right| > 0 \\\frac{2 \left(x + 1\right)^{\frac{3}{2}}}{3} + {G_{2, 2}^{1, 1}\left(\begin{matrix} 1 & \frac{11}{6} \\\frac{5}{6} & 0 \end{matrix} \middle| {x + 1} \right)} + {G_{2, 2}^{0, 2}\left(\begin{matrix} \frac{11}{6}, 1 & \\ & \frac{5}{6}, 0 \end{matrix} \middle| {x + 1} \right)} & \text{otherwese} \end{cases}

  3. Añadimos la constante de integración:

    {2(9(x+1)56+5(x+1)32)15forx+1>02(x+1)323+G2,21,1(1116560|x+1)+G2,20,2(116,156,0|x+1)otherwese+constant\begin{cases} \frac{2 \left(9 \left(x + 1\right)^{\frac{5}{6}} + 5 \left(x + 1\right)^{\frac{3}{2}}\right)}{15} & \text{for}\: \left|{x + 1}\right| > 0 \\\frac{2 \left(x + 1\right)^{\frac{3}{2}}}{3} + {G_{2, 2}^{1, 1}\left(\begin{matrix} 1 & \frac{11}{6} \\\frac{5}{6} & 0 \end{matrix} \middle| {x + 1} \right)} + {G_{2, 2}^{0, 2}\left(\begin{matrix} \frac{11}{6}, 1 & \\ & \frac{5}{6}, 0 \end{matrix} \middle| {x + 1} \right)} & \text{otherwese} \end{cases}+ \mathrm{constant}


Respuesta:

{2(9(x+1)56+5(x+1)32)15forx+1>02(x+1)323+G2,21,1(1116560|x+1)+G2,20,2(116,156,0|x+1)otherwese+constant\begin{cases} \frac{2 \left(9 \left(x + 1\right)^{\frac{5}{6}} + 5 \left(x + 1\right)^{\frac{3}{2}}\right)}{15} & \text{for}\: \left|{x + 1}\right| > 0 \\\frac{2 \left(x + 1\right)^{\frac{3}{2}}}{3} + {G_{2, 2}^{1, 1}\left(\begin{matrix} 1 & \frac{11}{6} \\\frac{5}{6} & 0 \end{matrix} \middle| {x + 1} \right)} + {G_{2, 2}^{0, 2}\left(\begin{matrix} \frac{11}{6}, 1 & \\ & \frac{5}{6}, 0 \end{matrix} \middle| {x + 1} \right)} & \text{otherwese} \end{cases}+ \mathrm{constant}

Respuesta (Indefinida) [src]
                                                        //                            5/6                                                 \
  /                                                     ||                     (1 + x)   *Gamma(5/6)                                      |
 |                                                3/2   ||                     ---------------------                       for |1 + x| > 0|
 | /      1            _______\          2*(x + 1)      ||                          Gamma(11/6)                                           |
 | |-------------- + \/ x + 1 | dx = C + ------------ + |<                                                                                |
 | |   ___________            |               3         || __1, 1 / 1   11/6 |      \    __0, 2 /11/6, 1         |      \                 |
 | |3 /   _______             |                         ||/__     |          | 1 + x| + /__     |                | 1 + x|     otherwise   |
 | \\/  \/ x + 1              /                         ||\_|2, 2 \5/6   0   |      /   \_|2, 2 \         5/6, 0 |      /                 |
 |                                                      \\                                                                                /
/                                                                                                                                          
(x+1+1x+13)dx=C+2(x+1)323+{(x+1)56Γ(56)Γ(116)forx+1>0G2,21,1(1116560|x+1)+G2,20,2(116,156,0|x+1)otherwise\int \left(\sqrt{x + 1} + \frac{1}{\sqrt[3]{\sqrt{x + 1}}}\right)\, dx = C + \frac{2 \left(x + 1\right)^{\frac{3}{2}}}{3} + \begin{cases} \frac{\left(x + 1\right)^{\frac{5}{6}} \Gamma\left(\frac{5}{6}\right)}{\Gamma\left(\frac{11}{6}\right)} & \text{for}\: \left|{x + 1}\right| > 0 \\{G_{2, 2}^{1, 1}\left(\begin{matrix} 1 & \frac{11}{6} \\\frac{5}{6} & 0 \end{matrix} \middle| {x + 1} \right)} + {G_{2, 2}^{0, 2}\left(\begin{matrix} \frac{11}{6}, 1 & \\ & \frac{5}{6}, 0 \end{matrix} \middle| {x + 1} \right)} & \text{otherwise} \end{cases}
Gráfica
0.001.000.100.200.300.400.500.600.700.800.900.05.0
Respuesta [src]
           ___      5/6
  28   4*\/ 2    6*2   
- -- + ------- + ------
  15      3        5   
2815+423+62565- \frac{28}{15} + \frac{4 \sqrt{2}}{3} + \frac{6 \cdot 2^{\frac{5}{6}}}{5}
=
=
           ___      5/6
  28   4*\/ 2    6*2   
- -- + ------- + ------
  15      3        5   
2815+423+62565- \frac{28}{15} + \frac{4 \sqrt{2}}{3} + \frac{6 \cdot 2^{\frac{5}{6}}}{5}
-28/15 + 4*sqrt(2)/3 + 6*2^(5/6)/5
Respuesta numérica [src]
2.15710834003427
2.15710834003427

    Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.