Sr Examen

Otras calculadoras:

Límite de la función (x+x^3-tan(10*x)+tan(sin(9*x)))/x^3

cuando
v

Para puntos concretos:

Gráfico:

interior superior

Definida a trozos:

Solución

Ha introducido [src]
     /     3                            \
     |x + x  - tan(10*x) + tan(sin(9*x))|
 lim |----------------------------------|
x->0+|                 3                |
     \                x                 /
$$\lim_{x \to 0^+}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right)$$
Limit((x + x^3 - tan(10*x) + tan(sin(9*x)))/x^3, x, 0)
Método de l'Hopital
Tenemos la indeterminación de tipo
0/0,

tal que el límite para el numerador es
$$\lim_{x \to 0^+}\left(x^{3} + x - \tan{\left(10 x \right)} + \tan{\left(\sin{\left(9 x \right)} \right)}\right) = 0$$
y el límite para el denominador es
$$\lim_{x \to 0^+} x^{3} = 0$$
Vamos a probar las derivadas del numerador y denominador hasta eliminar la indeterminación.
$$\lim_{x \to 0^+}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right)$$
=
Introducimos una pequeña modificación de la función bajo el signo del límite
$$\lim_{x \to 0^+}\left(\frac{x \left(x^{2} + 1\right) - \tan{\left(10 x \right)} + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(x^{3} + x - \tan{\left(10 x \right)} + \tan{\left(\sin{\left(9 x \right)} \right)}\right)}{\frac{d}{d x} x^{3}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{3 x^{2} + 9 \cos{\left(9 x \right)} \tan^{2}{\left(\sin{\left(9 x \right)} \right)} + 9 \cos{\left(9 x \right)} - 10 \tan^{2}{\left(10 x \right)} - 9}{3 x^{2}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(3 x^{2} + 9 \cos{\left(9 x \right)} \tan^{2}{\left(\sin{\left(9 x \right)} \right)} + 9 \cos{\left(9 x \right)} - 10 \tan^{2}{\left(10 x \right)} - 9\right)}{\frac{d}{d x} 3 x^{2}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{6 x - 81 \sin{\left(9 x \right)} \tan^{2}{\left(\sin{\left(9 x \right)} \right)} - 81 \sin{\left(9 x \right)} + 162 \cos^{2}{\left(9 x \right)} \tan^{3}{\left(\sin{\left(9 x \right)} \right)} + 162 \cos^{2}{\left(9 x \right)} \tan{\left(\sin{\left(9 x \right)} \right)} - 200 \tan^{3}{\left(10 x \right)} - 200 \tan{\left(10 x \right)}}{6 x}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(6 x - 81 \sin{\left(9 x \right)} \tan^{2}{\left(\sin{\left(9 x \right)} \right)} - 81 \sin{\left(9 x \right)} + 162 \cos^{2}{\left(9 x \right)} \tan^{3}{\left(\sin{\left(9 x \right)} \right)} + 162 \cos^{2}{\left(9 x \right)} \tan{\left(\sin{\left(9 x \right)} \right)} - 200 \tan^{3}{\left(10 x \right)} - 200 \tan{\left(10 x \right)}\right)}{\frac{d}{d x} 6 x}\right)$$
=
$$\lim_{x \to 0^+}\left(- 729 \sin{\left(9 x \right)} \cos{\left(9 x \right)} \tan^{3}{\left(\sin{\left(9 x \right)} \right)} - 729 \sin{\left(9 x \right)} \cos{\left(9 x \right)} \tan{\left(\sin{\left(9 x \right)} \right)} + 729 \cos^{3}{\left(9 x \right)} \tan^{4}{\left(\sin{\left(9 x \right)} \right)} + 972 \cos^{3}{\left(9 x \right)} \tan^{2}{\left(\sin{\left(9 x \right)} \right)} + 243 \cos^{3}{\left(9 x \right)} - \frac{243 \cos{\left(9 x \right)} \tan^{2}{\left(\sin{\left(9 x \right)} \right)}}{2} - \frac{243 \cos{\left(9 x \right)}}{2} - 1000 \tan^{4}{\left(10 x \right)} - \frac{4000 \tan^{2}{\left(10 x \right)}}{3} - \frac{997}{3}\right)$$
=
$$\lim_{x \to 0^+}\left(- 729 \sin{\left(9 x \right)} \cos{\left(9 x \right)} \tan^{3}{\left(\sin{\left(9 x \right)} \right)} - 729 \sin{\left(9 x \right)} \cos{\left(9 x \right)} \tan{\left(\sin{\left(9 x \right)} \right)} + 729 \cos^{3}{\left(9 x \right)} \tan^{4}{\left(\sin{\left(9 x \right)} \right)} + 972 \cos^{3}{\left(9 x \right)} \tan^{2}{\left(\sin{\left(9 x \right)} \right)} + 243 \cos^{3}{\left(9 x \right)} - \frac{243 \cos{\left(9 x \right)} \tan^{2}{\left(\sin{\left(9 x \right)} \right)}}{2} - \frac{243 \cos{\left(9 x \right)}}{2} - 1000 \tan^{4}{\left(10 x \right)} - \frac{4000 \tan^{2}{\left(10 x \right)}}{3} - \frac{997}{3}\right)$$
=
$$- \frac{1265}{6}$$
Como puedes ver, hemos aplicado el método de l'Hopital (utilizando la derivada del numerador y denominador) 3 vez (veces)
Gráfica
Respuesta rápida [src]
-1265/6
$$- \frac{1265}{6}$$
Otros límites con x→0, -oo, +oo, 1
$$\lim_{x \to 0^-}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right) = - \frac{1265}{6}$$
Más detalles con x→0 a la izquierda
$$\lim_{x \to 0^+}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right) = - \frac{1265}{6}$$
$$\lim_{x \to \infty}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right)$$
Más detalles con x→oo
$$\lim_{x \to 1^-}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right) = - \tan{\left(10 \right)} + \tan{\left(\sin{\left(9 \right)} \right)} + 2$$
Más detalles con x→1 a la izquierda
$$\lim_{x \to 1^+}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right) = - \tan{\left(10 \right)} + \tan{\left(\sin{\left(9 \right)} \right)} + 2$$
Más detalles con x→1 a la derecha
$$\lim_{x \to -\infty}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right)$$
Más detalles con x→-oo
A la izquierda y a la derecha [src]
     /     3                            \
     |x + x  - tan(10*x) + tan(sin(9*x))|
 lim |----------------------------------|
x->0+|                 3                |
     \                x                 /
$$\lim_{x \to 0^+}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right)$$
-1265/6
$$- \frac{1265}{6}$$
= -210.833333333333
     /     3                            \
     |x + x  - tan(10*x) + tan(sin(9*x))|
 lim |----------------------------------|
x->0-|                 3                |
     \                x                 /
$$\lim_{x \to 0^-}\left(\frac{\left(\left(x^{3} + x\right) - \tan{\left(10 x \right)}\right) + \tan{\left(\sin{\left(9 x \right)} \right)}}{x^{3}}\right)$$
-1265/6
$$- \frac{1265}{6}$$
= -210.833333333333
= -210.833333333333
Respuesta numérica [src]
-210.833333333333
-210.833333333333