Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{2 x^{3} - 2 x^{2}}{5 x^{3} - 4 x^{2}}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{2 x^{3} - 2 x^{2}}{5 x^{3} - 4 x^{2}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{2 x^{2} \left(x - 1\right)}{x^{2} \left(5 x - 4\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{2 \left(x - 1\right)}{5 x - 4}\right) = $$
$$\frac{\left(-1\right) 2}{-4 + 0 \cdot 5} = $$
= 1/2
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{2 x^{3} - 2 x^{2}}{5 x^{3} - 4 x^{2}}\right) = \frac{1}{2}$$