Tomamos como el límite
$$\lim_{x \to 2^+}\left(\frac{3 x^{2} + \left(- x - 10\right)}{- 7 x^{2} - 10}\right)$$
cambiamos
$$\lim_{x \to 2^+}\left(\frac{3 x^{2} + \left(- x - 10\right)}{- 7 x^{2} - 10}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{\left(x - 2\right) \left(3 x + 5\right)}{- 7 x^{2} - 10}\right)$$
=
$$\lim_{x \to 2^+}\left(- \frac{\left(x - 2\right) \left(3 x + 5\right)}{7 x^{2} + 10}\right) = $$
$$- \frac{\left(-2 + 2\right) \left(5 + 2 \cdot 3\right)}{10 + 7 \cdot 2^{2}} = $$
= 0
Entonces la respuesta definitiva es:
$$\lim_{x \to 2^+}\left(\frac{3 x^{2} + \left(- x - 10\right)}{- 7 x^{2} - 10}\right) = 0$$