Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{- 5 x + \left(- x^{2} - 14\right)}{2 x^{2} + \left(- 9 x - 35\right)}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{- 5 x + \left(- x^{2} - 14\right)}{2 x^{2} + \left(- 9 x - 35\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{- x^{2} - 5 x - 14}{\left(x - 7\right) \left(2 x + 5\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(- \frac{x^{2} + 5 x + 14}{\left(x - 7\right) \left(2 x + 5\right)}\right) = $$
$$- \frac{0^{2} + 0 \cdot 5 + 14}{\left(-1\right) 7 \left(0 \cdot 2 + 5\right)} = $$
= 2/5
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{- 5 x + \left(- x^{2} - 14\right)}{2 x^{2} + \left(- 9 x - 35\right)}\right) = \frac{2}{5}$$