Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{\left(x^{3} - 1\right) \left(x^{4} + 8\right)}{4 x^{3} + \left(3 x^{2} + 2\right)}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{\left(x^{3} - 1\right) \left(x^{4} + 8\right)}{4 x^{3} + \left(3 x^{2} + 2\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\left(x - 1\right) \left(x^{4} + 8\right) \left(x^{2} + x + 1\right)}{4 x^{3} + 3 x^{2} + 2}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{x^{7} - x^{4} + 8 x^{3} - 8}{4 x^{3} + 3 x^{2} + 2}\right) = $$
$$\frac{-8 + 0^{7} - 0^{4} + 8 \cdot 0^{3}}{3 \cdot 0^{2} + 4 \cdot 0^{3} + 2} = $$
= -4
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{\left(x^{3} - 1\right) \left(x^{4} + 8\right)}{4 x^{3} + \left(3 x^{2} + 2\right)}\right) = -4$$