Tenemos la indeterminación de tipo
oo/oo,
tal que el límite para el numerador es
$$\lim_{x \to \infty} x^{x} = \infty$$
y el límite para el denominador es
$$\lim_{x \to \infty} \left(x + 1\right)^{x + 1} = \infty$$
Vamos a probar las derivadas del numerador y denominador hasta eliminar la indeterminación.
$$\lim_{x \to \infty}\left(x^{x} \left(x + 1\right)^{- x - 1}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{\frac{d}{d x} x^{x}}{\frac{d}{d x} \left(x + 1\right)^{x + 1}}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{x^{x} \left(x + 1\right)^{- x - 1} \left(\log{\left(x \right)} + 1\right)}{\log{\left(x + 1 \right)} + 1}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{\frac{d}{d x} \frac{x^{x} \left(\log{\left(x \right)} + 1\right)}{\log{\left(x + 1 \right)} + 1}}{\frac{d}{d x} \left(x + 1\right)^{x + 1}}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{- \frac{x^{x} \log{\left(x \right)}}{x \log{\left(x + 1 \right)}^{2} + 2 x \log{\left(x + 1 \right)} + x + \log{\left(x + 1 \right)}^{2} + 2 \log{\left(x + 1 \right)} + 1} - \frac{x^{x}}{x \log{\left(x + 1 \right)}^{2} + 2 x \log{\left(x + 1 \right)} + x + \log{\left(x + 1 \right)}^{2} + 2 \log{\left(x + 1 \right)} + 1} + \frac{x^{x} \log{\left(x \right)}^{2}}{\log{\left(x + 1 \right)} + 1} + \frac{2 x^{x} \log{\left(x \right)}}{\log{\left(x + 1 \right)} + 1} + \frac{x^{x}}{\log{\left(x + 1 \right)} + 1} + \frac{x^{x}}{x \log{\left(x + 1 \right)} + x}}{x \left(x + 1\right)^{x} \log{\left(x + 1 \right)} + x \left(x + 1\right)^{x} + \left(x + 1\right)^{x} \log{\left(x + 1 \right)} + \left(x + 1\right)^{x}}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{- \frac{x^{x} \log{\left(x \right)}}{x \log{\left(x + 1 \right)}^{2} + 2 x \log{\left(x + 1 \right)} + x + \log{\left(x + 1 \right)}^{2} + 2 \log{\left(x + 1 \right)} + 1} - \frac{x^{x}}{x \log{\left(x + 1 \right)}^{2} + 2 x \log{\left(x + 1 \right)} + x + \log{\left(x + 1 \right)}^{2} + 2 \log{\left(x + 1 \right)} + 1} + \frac{x^{x} \log{\left(x \right)}^{2}}{\log{\left(x + 1 \right)} + 1} + \frac{2 x^{x} \log{\left(x \right)}}{\log{\left(x + 1 \right)} + 1} + \frac{x^{x}}{\log{\left(x + 1 \right)} + 1} + \frac{x^{x}}{x \log{\left(x + 1 \right)} + x}}{x \left(x + 1\right)^{x} \log{\left(x + 1 \right)} + x \left(x + 1\right)^{x} + \left(x + 1\right)^{x} \log{\left(x + 1 \right)} + \left(x + 1\right)^{x}}\right)$$
=
$$0$$
Como puedes ver, hemos aplicado el método de l'Hopital (utilizando la derivada del numerador y denominador) 2 vez (veces)