Tomamos como el límite
$$\lim_{x \to 1^+}\left(\frac{5 x + \left(4 x^{2} + \left(x^{3} + 2\right)\right)}{- 3 x + \left(x^{3} - 2\right)}\right)$$
cambiamos
$$\lim_{x \to 1^+}\left(\frac{5 x + \left(4 x^{2} + \left(x^{3} + 2\right)\right)}{- 3 x + \left(x^{3} - 2\right)}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{\left(x + 1\right)^{2} \left(x + 2\right)}{\left(x - 2\right) \left(x + 1\right)^{2}}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{x + 2}{x - 2}\right) = $$
$$\frac{1 + 2}{-2 + 1} = $$
= -3
Entonces la respuesta definitiva es:
$$\lim_{x \to 1^+}\left(\frac{5 x + \left(4 x^{2} + \left(x^{3} + 2\right)\right)}{- 3 x + \left(x^{3} - 2\right)}\right) = -3$$