Expresión b(((¬(ab)⇒c)⇒b)⇒(a¬c⇔a+b))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
$$\neg \left(a \wedge b\right) \Rightarrow c = c \vee \left(a \wedge b\right)$$
$$\left(\neg \left(a \wedge b\right) \Rightarrow c\right) \Rightarrow b = b \vee \neg c$$
$$\left(a \wedge \neg c\right) ⇔ \left(a \vee b\right) = \left(a \wedge \neg c\right) \vee \left(\neg a \wedge \neg b\right)$$
$$\left(\left(\neg \left(a \wedge b\right) \Rightarrow c\right) \Rightarrow b\right) \Rightarrow \left(\left(a \wedge \neg c\right) ⇔ \left(a \vee b\right)\right) = \left(a \wedge \neg c\right) \vee \neg b$$
$$b \wedge \left(\left(\left(\neg \left(a \wedge b\right) \Rightarrow c\right) \Rightarrow b\right) \Rightarrow \left(\left(a \wedge \neg c\right) ⇔ \left(a \vee b\right)\right)\right) = a \wedge b \wedge \neg c$$
$$a \wedge b \wedge \neg c$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
Ya está reducido a FND
$$a \wedge b \wedge \neg c$$
$$a \wedge b \wedge \neg c$$
Ya está reducido a FNC
$$a \wedge b \wedge \neg c$$
$$a \wedge b \wedge \neg c$$