Expresión (¬av¬bv¬c)&(¬a&¬b&c)v(¬a&b&¬c)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$c \wedge \neg a \wedge \neg b \wedge \left(\neg a \vee \neg b \vee \neg c\right) = c \wedge \neg a \wedge \neg b$$
$$\left(b \wedge \neg a \wedge \neg c\right) \vee \left(c \wedge \neg a \wedge \neg b \wedge \left(\neg a \vee \neg b \vee \neg c\right)\right) = \neg a \wedge \left(b \vee c\right) \wedge \left(\neg b \vee \neg c\right)$$
$$\neg a \wedge \left(b \vee c\right) \wedge \left(\neg b \vee \neg c\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
$$\neg a \wedge \left(b \vee c\right) \wedge \left(\neg b \vee \neg c\right)$$
$$\left(b \wedge \neg a \wedge \neg c\right) \vee \left(c \wedge \neg a \wedge \neg b\right)$$
(b∧(¬a)∧(¬c))∨(c∧(¬a)∧(¬b))
Ya está reducido a FNC
$$\neg a \wedge \left(b \vee c\right) \wedge \left(\neg b \vee \neg c\right)$$
$$\left(b \wedge \neg a \wedge \neg b\right) \vee \left(b \wedge \neg a \wedge \neg c\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(c \wedge \neg a \wedge \neg c\right)$$
(b∧(¬a)∧(¬b))∨(b∧(¬a)∧(¬c))∨(c∧(¬a)∧(¬b))∨(c∧(¬a)∧(¬c))