Expresión zvxvyv!(xvy&!zvz&!y)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
¬(x∨(y∧¬z)∨(z∧¬y))=¬x∧(y∨¬z)∧(z∨¬y)x∨y∨z∨¬(x∨(y∧¬z)∨(z∧¬y))=1
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+