Sr Examen

Expresión bvне(a)&не(c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    b∨((¬a)∧(¬c))
    $$b \vee \left(\neg a \wedge \neg c\right)$$
    Simplificación [src]
    $$b \vee \left(\neg a \wedge \neg c\right)$$
    b∨((¬a)∧(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    $$\left(b \vee \neg a\right) \wedge \left(b \vee \neg c\right)$$
    (b∨(¬a))∧(b∨(¬c))
    FND [src]
    Ya está reducido a FND
    $$b \vee \left(\neg a \wedge \neg c\right)$$
    b∨((¬a)∧(¬c))
    FNC [src]
    $$\left(b \vee \neg a\right) \wedge \left(b \vee \neg c\right)$$
    (b∨(¬a))∧(b∨(¬c))
    FNDP [src]
    $$b \vee \left(\neg a \wedge \neg c\right)$$
    b∨((¬a)∧(¬c))