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Lógica matemática/ ~(x&y)>z

Expresión ~(x&y)>z

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    Solución

    Ha introducido [src] 
    (¬(x∧y))⇒z
    ¬(x∧y)⇒z\neg \left(x \wedge y\right) \Rightarrow z
    Solución detallada
    ¬(x∧y)=¬x∨¬y\neg \left(x \wedge y\right) = \neg x \vee \neg y
    ¬(x∧y)⇒z=z∨(x∧y)\neg \left(x \wedge y\right) \Rightarrow z = z \vee \left(x \wedge y\right)
    Simplificación [src]
    z∨(x∧y)z \vee \left(x \wedge y\right) 
    z∨(x∧y)
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    (x∨z)∧(y∨z)\left(x \vee z\right) \wedge \left(y \vee z\right) 
    (x∨z)∧(y∨z)
    FND [src]
    Ya está reducido a FND
    z∨(x∧y)z \vee \left(x \wedge y\right) 
    z∨(x∧y)
    FNC [src]
    (x∨z)∧(y∨z)\left(x \vee z\right) \wedge \left(y \vee z\right) 
    (x∨z)∧(y∨z)
    FNDP [src]
    z∨(x∧y)z \vee \left(x \wedge y\right) 
    z∨(x∧y)
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