Expresión notz<->not(x->(notyvz))
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Solución
Solución detallada
$$x \Rightarrow \left(z \vee \neg y\right) = z \vee \neg x \vee \neg y$$
$$x \not\Rightarrow \left(z \vee \neg y\right) = x \wedge y \wedge \neg z$$
$$\neg z ⇔ x \not\Rightarrow \left(z \vee \neg y\right) = z \vee \left(x \wedge y\right)$$
$$z \vee \left(x \wedge y\right)$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$z \vee \left(x \wedge y\right)$$
Ya está reducido a FND
$$z \vee \left(x \wedge y\right)$$
$$\left(x \vee z\right) \wedge \left(y \vee z\right)$$
$$\left(x \vee z\right) \wedge \left(y \vee z\right)$$