Expresión (xy)v(yz)v(xt)v(zt)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
(t∧x)∨(t∧z)∨(x∧y)∨(y∧z)
Tabla de verdad
+---+---+---+---+--------+
| t | x | y | z | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
(t∧x)∨(t∧z)∨(x∧y)∨(y∧z)
(t∨y)∧(x∨z)∧(t∨x∨y)∧(t∨x∨z)∧(t∨y∨z)∧(x∨y∨z)∧(t∨x∨y∨z)
(t∨y)∧(x∨z)∧(t∨x∨y)∧(t∨x∨z)∧(t∨y∨z)∧(x∨y∨z)∧(t∨x∨y∨z)
(t∨y)∧(x∨z)
Ya está reducido a FND
(t∧x)∨(t∧z)∨(x∧y)∨(y∧z)