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Expresión (¬a∨¬(abc)∨¬c)(a¬c∨c¬x∨x)¬(ac∨bx)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬((a∧c)∨(b∧x)))∧(x∨(a∧(¬c))∨(c∧(¬x)))∧((¬a)∨(¬c)∨(¬(a∧b∧c)))
    $$\neg \left(\left(a \wedge c\right) \vee \left(b \wedge x\right)\right) \wedge \left(x \vee \left(a \wedge \neg c\right) \vee \left(c \wedge \neg x\right)\right) \wedge \left(\neg a \vee \neg c \vee \neg \left(a \wedge b \wedge c\right)\right)$$
    Solución detallada
    $$\left(a \wedge c\right) \vee \left(b \wedge x\right) = \left(a \vee b\right) \wedge \left(a \vee x\right) \wedge \left(b \vee c\right) \wedge \left(c \vee x\right)$$
    $$\neg \left(\left(a \wedge c\right) \vee \left(b \wedge x\right)\right) = \left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg x\right) \vee \left(\neg b \wedge \neg c\right) \vee \left(\neg c \wedge \neg x\right)$$
    $$x \vee \left(a \wedge \neg c\right) \vee \left(c \wedge \neg x\right) = a \vee c \vee x$$
    $$\neg \left(a \wedge b \wedge c\right) = \neg a \vee \neg b \vee \neg c$$
    $$\neg a \vee \neg c \vee \neg \left(a \wedge b \wedge c\right) = \neg a \vee \neg b \vee \neg c$$
    $$\neg \left(\left(a \wedge c\right) \vee \left(b \wedge x\right)\right) \wedge \left(x \vee \left(a \wedge \neg c\right) \vee \left(c \wedge \neg x\right)\right) \wedge \left(\neg a \vee \neg c \vee \neg \left(a \wedge b \wedge c\right)\right) = \left(\neg a \vee \neg c\right) \wedge \left(\neg b \vee \neg x\right) \wedge \left(a \vee c \vee x\right)$$
    Simplificación [src]
    $$\left(\neg a \vee \neg c\right) \wedge \left(\neg b \vee \neg x\right) \wedge \left(a \vee c \vee x\right)$$
    (a∨c∨x)∧((¬a)∨(¬c))∧((¬b)∨(¬x))
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | x | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    FNCD [src]
    $$\left(\neg a \vee \neg c\right) \wedge \left(\neg b \vee \neg x\right) \wedge \left(a \vee c \vee x\right)$$
    (a∨c∨x)∧((¬a)∨(¬c))∧((¬b)∨(¬x))
    FND [src]
    $$\left(a \wedge \neg a \wedge \neg b\right) \vee \left(a \wedge \neg a \wedge \neg x\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(a \wedge \neg c \wedge \neg x\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(c \wedge \neg a \wedge \neg x\right) \vee \left(c \wedge \neg b \wedge \neg c\right) \vee \left(c \wedge \neg c \wedge \neg x\right) \vee \left(x \wedge \neg a \wedge \neg b\right) \vee \left(x \wedge \neg a \wedge \neg x\right) \vee \left(x \wedge \neg b \wedge \neg c\right) \vee \left(x \wedge \neg c \wedge \neg x\right)$$
    (a∧(¬a)∧(¬b))∨(a∧(¬a)∧(¬x))∨(a∧(¬b)∧(¬c))∨(a∧(¬c)∧(¬x))∨(c∧(¬a)∧(¬b))∨(c∧(¬a)∧(¬x))∨(c∧(¬b)∧(¬c))∨(c∧(¬c)∧(¬x))∨(x∧(¬a)∧(¬b))∨(x∧(¬a)∧(¬x))∨(x∧(¬b)∧(¬c))∨(x∧(¬c)∧(¬x))
    FNC [src]
    Ya está reducido a FNC
    $$\left(\neg a \vee \neg c\right) \wedge \left(\neg b \vee \neg x\right) \wedge \left(a \vee c \vee x\right)$$
    (a∨c∨x)∧((¬a)∨(¬c))∧((¬b)∨(¬x))
    FNDP [src]
    $$\left(a \wedge \neg c \wedge \neg x\right) \vee \left(c \wedge \neg a \wedge \neg x\right) \vee \left(x \wedge \neg a \wedge \neg b\right) \vee \left(x \wedge \neg b \wedge \neg c\right)$$
    (a∧(¬c)∧(¬x))∨(c∧(¬a)∧(¬x))∨(x∧(¬a)∧(¬b))∨(x∧(¬b)∧(¬c))