Expresión xyz∨xy¬z∨¬z
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(x∧y∧z)∨(x∧y∧¬z)∨¬z=(x∧y)∨¬z
(x∧y)∨¬z
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(x∨¬z)∧(y∨¬z)
(x∨¬z)∧(y∨¬z)
(x∧y)∨¬z
Ya está reducido a FND
(x∧y)∨¬z