Expresión ¬(¬(xy)&(x¬yzv¬xy))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(x \wedge y\right) = \neg x \vee \neg y$$
$$\left(y \wedge \neg x\right) \vee \left(x \wedge z \wedge \neg y\right) = \left(x \vee y\right) \wedge \left(y \vee z\right) \wedge \left(\neg x \vee \neg y\right)$$
$$\neg \left(x \wedge y\right) \wedge \left(\left(y \wedge \neg x\right) \vee \left(x \wedge z \wedge \neg y\right)\right) = \left(x \vee y\right) \wedge \left(y \vee z\right) \wedge \left(\neg x \vee \neg y\right)$$
$$\neg \left(\neg \left(x \wedge y\right) \wedge \left(\left(y \wedge \neg x\right) \vee \left(x \wedge z \wedge \neg y\right)\right)\right) = \left(x \wedge y\right) \vee \left(\neg x \wedge \neg y\right) \vee \left(\neg y \wedge \neg z\right)$$
$$\left(x \wedge y\right) \vee \left(\neg x \wedge \neg y\right) \vee \left(\neg y \wedge \neg z\right)$$
(x∧y)∨((¬x)∧(¬y))∨((¬y)∧(¬z))
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(x \vee \neg y\right) \wedge \left(y \vee \neg y\right) \wedge \left(x \vee \neg x \vee \neg y\right) \wedge \left(x \vee \neg x \vee \neg z\right) \wedge \left(x \vee \neg y \vee \neg z\right) \wedge \left(y \vee \neg x \vee \neg y\right) \wedge \left(y \vee \neg x \vee \neg z\right) \wedge \left(y \vee \neg y \vee \neg z\right)$$
(x∨(¬y))∧(y∨(¬y))∧(x∨(¬x)∨(¬y))∧(x∨(¬x)∨(¬z))∧(x∨(¬y)∨(¬z))∧(y∨(¬x)∨(¬y))∧(y∨(¬x)∨(¬z))∧(y∨(¬y)∨(¬z))
$$\left(x \vee \neg y\right) \wedge \left(y \vee \neg x \vee \neg z\right)$$
$$\left(x \wedge y\right) \vee \left(\neg x \wedge \neg y\right) \vee \left(\neg y \wedge \neg z\right)$$
(x∧y)∨((¬x)∧(¬y))∨((¬y)∧(¬z))
Ya está reducido a FND
$$\left(x \wedge y\right) \vee \left(\neg x \wedge \neg y\right) \vee \left(\neg y \wedge \neg z\right)$$
(x∧y)∨((¬x)∧(¬y))∨((¬y)∧(¬z))