Sr Examen

Expresión xyz||xy!z||!xy||x!yz

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (y∧(¬x))∨(x∧y∧z)∨(x∧y∧(¬z))∨(x∧z∧(¬y))
    $$\left(y \wedge \neg x\right) \vee \left(x \wedge y \wedge z\right) \vee \left(x \wedge y \wedge \neg z\right) \vee \left(x \wedge z \wedge \neg y\right)$$
    Solución detallada
    $$\left(y \wedge \neg x\right) \vee \left(x \wedge y \wedge z\right) \vee \left(x \wedge y \wedge \neg z\right) \vee \left(x \wedge z \wedge \neg y\right) = y \vee \left(x \wedge z\right)$$
    Simplificación [src]
    $$y \vee \left(x \wedge z\right)$$
    y∨(x∧z)
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    $$\left(x \vee y\right) \wedge \left(y \vee z\right)$$
    (x∨y)∧(y∨z)
    FNDP [src]
    $$y \vee \left(x \wedge z\right)$$
    y∨(x∧z)
    FNC [src]
    $$\left(x \vee y\right) \wedge \left(y \vee z\right)$$
    (x∨y)∧(y∨z)
    FND [src]
    Ya está reducido a FND
    $$y \vee \left(x \wedge z\right)$$
    y∨(x∧z)