Sr Examen
Expresión ab^+c+(a+b)c+da
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
c∨(a∧b)∨(a∧d)∨(c∧(a∨b))
$$c \vee \left(a \wedge b\right) \vee \left(a \wedge d\right) \vee \left(c \wedge \left(a \vee b\right)\right)$$
Solución detallada
$$c \vee \left(a \wedge b\right) \vee \left(a \wedge d\right) \vee \left(c \wedge \left(a \vee b\right)\right) = c \vee \left(a \wedge b\right) \vee \left(a \wedge d\right)$$
Tabla de verdad
+---+---+---+---+--------+ | a | b | c | d | result | +===+===+===+===+========+ | 0 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 0 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 0 | 1 | +---+---+---+---+--------+ | 0 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 1 | 0 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+
FNC
[src]
$$\left(a \vee c\right) \wedge \left(a \vee b \vee c\right) \wedge \left(a \vee c \vee d\right) \wedge \left(b \vee c \vee d\right)$$
(a∨c)∧(a∨b∨c)∧(a∨c∨d)∧(b∨c∨d)
FND
[src]
Ya está reducido a FND
$$c \vee \left(a \wedge b\right) \vee \left(a \wedge d\right)$$
c∨(a∧b)∨(a∧d)