Expresión ¬(¬(a&b)v¬(cvb)&(avc))v¬(bvc)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(b \vee c\right) = \neg b \wedge \neg c$$
$$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
$$\neg \left(b \vee c\right) \wedge \left(a \vee c\right) = a \wedge \neg b \wedge \neg c$$
$$\left(\neg \left(b \vee c\right) \wedge \left(a \vee c\right)\right) \vee \neg \left(a \wedge b\right) = \neg a \vee \neg b$$
$$\neg \left(\left(\neg \left(b \vee c\right) \wedge \left(a \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right) = a \wedge b$$
$$\neg \left(b \vee c\right) \vee \neg \left(\left(\neg \left(b \vee c\right) \wedge \left(a \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right) = \left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
$$\left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FND
$$\left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
$$\left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
$$\left(a \vee \neg b\right) \wedge \left(b \vee \neg c\right)$$
$$\left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg b\right) \wedge \left(b \vee \neg c\right)$$
(a∨(¬b))∧(a∨(¬c))∧(b∨(¬b))∧(b∨(¬c))