Sr Examen

Expresión ¬(¬(a&b)v¬(cvb)&(avc))v¬(bvc)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬(b∨c))∨(¬((¬(a∧b))∨((a∨c)∧(¬(b∨c)))))
    $$\neg \left(b \vee c\right) \vee \neg \left(\left(\neg \left(b \vee c\right) \wedge \left(a \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right)$$
    Solución detallada
    $$\neg \left(b \vee c\right) = \neg b \wedge \neg c$$
    $$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
    $$\neg \left(b \vee c\right) \wedge \left(a \vee c\right) = a \wedge \neg b \wedge \neg c$$
    $$\left(\neg \left(b \vee c\right) \wedge \left(a \vee c\right)\right) \vee \neg \left(a \wedge b\right) = \neg a \vee \neg b$$
    $$\neg \left(\left(\neg \left(b \vee c\right) \wedge \left(a \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right) = a \wedge b$$
    $$\neg \left(b \vee c\right) \vee \neg \left(\left(\neg \left(b \vee c\right) \wedge \left(a \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right) = \left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
    Simplificación [src]
    $$\left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
    (a∧b)∨((¬b)∧(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
    (a∧b)∨((¬b)∧(¬c))
    FNDP [src]
    $$\left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
    (a∧b)∨((¬b)∧(¬c))
    FNCD [src]
    $$\left(a \vee \neg b\right) \wedge \left(b \vee \neg c\right)$$
    (a∨(¬b))∧(b∨(¬c))
    FNC [src]
    $$\left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg b\right) \wedge \left(b \vee \neg c\right)$$
    (a∨(¬b))∧(a∨(¬c))∧(b∨(¬b))∧(b∨(¬c))