Expresión ¬((¬x&(y&z))&(¬xv¬y))&xv(y&¬z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$y \wedge z \wedge \neg x \wedge \left(\neg x \vee \neg y\right) = y \wedge z \wedge \neg x$$
$$\neg \left(y \wedge z \wedge \neg x \wedge \left(\neg x \vee \neg y\right)\right) = x \vee \neg y \vee \neg z$$
$$x \wedge \neg \left(y \wedge z \wedge \neg x \wedge \left(\neg x \vee \neg y\right)\right) = x$$
$$\left(x \wedge \neg \left(y \wedge z \wedge \neg x \wedge \left(\neg x \vee \neg y\right)\right)\right) \vee \left(y \wedge \neg z\right) = x \vee \left(y \wedge \neg z\right)$$
$$x \vee \left(y \wedge \neg z\right)$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$x \vee \left(y \wedge \neg z\right)$$
$$\left(x \vee y\right) \wedge \left(x \vee \neg z\right)$$
$$\left(x \vee y\right) \wedge \left(x \vee \neg z\right)$$
Ya está reducido a FND
$$x \vee \left(y \wedge \neg z\right)$$