Sr Examen

Expresión ¬((¬x&(y&z))&(¬xv¬y))&xv(y&¬z)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (y∧(¬z))∨(x∧(¬(y∧z∧(¬x)∧((¬x)∨(¬y)))))
    $$\left(x \wedge \neg \left(y \wedge z \wedge \neg x \wedge \left(\neg x \vee \neg y\right)\right)\right) \vee \left(y \wedge \neg z\right)$$
    Solución detallada
    $$y \wedge z \wedge \neg x \wedge \left(\neg x \vee \neg y\right) = y \wedge z \wedge \neg x$$
    $$\neg \left(y \wedge z \wedge \neg x \wedge \left(\neg x \vee \neg y\right)\right) = x \vee \neg y \vee \neg z$$
    $$x \wedge \neg \left(y \wedge z \wedge \neg x \wedge \left(\neg x \vee \neg y\right)\right) = x$$
    $$\left(x \wedge \neg \left(y \wedge z \wedge \neg x \wedge \left(\neg x \vee \neg y\right)\right)\right) \vee \left(y \wedge \neg z\right) = x \vee \left(y \wedge \neg z\right)$$
    Simplificación [src]
    $$x \vee \left(y \wedge \neg z\right)$$
    x∨(y∧(¬z))
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    $$x \vee \left(y \wedge \neg z\right)$$
    x∨(y∧(¬z))
    FNCD [src]
    $$\left(x \vee y\right) \wedge \left(x \vee \neg z\right)$$
    (x∨y)∧(x∨(¬z))
    FNC [src]
    $$\left(x \vee y\right) \wedge \left(x \vee \neg z\right)$$
    (x∨y)∧(x∨(¬z))
    FND [src]
    Ya está reducido a FND
    $$x \vee \left(y \wedge \neg z\right)$$
    x∨(y∧(¬z))