Sr Examen
Expresión !(x&!yvz)&!(yv!z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(¬(y∨(¬z)))∧(¬(z∨(x∧(¬y))))
$$\neg \left(y \vee \neg z\right) \wedge \neg \left(z \vee \left(x \wedge \neg y\right)\right)$$
Solución detallada
$$\neg \left(y \vee \neg z\right) = z \wedge \neg y$$
$$\neg \left(z \vee \left(x \wedge \neg y\right)\right) = \neg z \wedge \left(y \vee \neg x\right)$$
$$\neg \left(y \vee \neg z\right) \wedge \neg \left(z \vee \left(x \wedge \neg y\right)\right) = \text{False}$$
$$\neg \left(z \vee \left(x \wedge \neg y\right)\right) = \neg z \wedge \left(y \vee \neg x\right)$$
$$\neg \left(y \vee \neg z\right) \wedge \neg \left(z \vee \left(x \wedge \neg y\right)\right) = \text{False}$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+