Sr Examen
Expresión xyz+x¬yz+x
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
x∨(x∧y∧z)∨(x∧z∧(¬y))
$$x \vee \left(x \wedge y \wedge z\right) \vee \left(x \wedge z \wedge \neg y\right)$$
Solución detallada
$$x \vee \left(x \wedge y \wedge z\right) \vee \left(x \wedge z \wedge \neg y\right) = x$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+