Sr Examen

Expresión xyz+x¬yz+x

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    x∨(x∧y∧z)∨(x∧z∧(¬y))
    x(xyz)(xz¬y)x \vee \left(x \wedge y \wedge z\right) \vee \left(x \wedge z \wedge \neg y\right)
    Solución detallada
    x(xyz)(xz¬y)=xx \vee \left(x \wedge y \wedge z\right) \vee \left(x \wedge z \wedge \neg y\right) = x
    Simplificación [src]
    xx
    x
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    xx
    x
    FNCD [src]
    xx
    x
    FND [src]
    Ya está reducido a FND
    xx
    x
    FNC [src]
    Ya está reducido a FNC
    xx
    x