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Expresión (((¬(a∨b)∧(a∨c))∧¬b)∨¬a)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬a)∨((¬b)∧(a∨c)∧(¬(a∨b)))
    $$\left(\neg b \wedge \neg \left(a \vee b\right) \wedge \left(a \vee c\right)\right) \vee \neg a$$
    Solución detallada
    $$\neg \left(a \vee b\right) = \neg a \wedge \neg b$$
    $$\neg b \wedge \neg \left(a \vee b\right) \wedge \left(a \vee c\right) = c \wedge \neg a \wedge \neg b$$
    $$\left(\neg b \wedge \neg \left(a \vee b\right) \wedge \left(a \vee c\right)\right) \vee \neg a = \neg a$$
    Simplificación [src]
    $$\neg a$$
    ¬a
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNDP [src]
    $$\neg a$$
    ¬a
    FNCD [src]
    $$\neg a$$
    ¬a
    FNC [src]
    Ya está reducido a FNC
    $$\neg a$$
    ¬a
    FND [src]
    Ya está reducido a FND
    $$\neg a$$
    ¬a