Expresión xy∨(¬(x⇒x¬y)⇒z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
x⇒(x∧¬y)=¬x∨¬yx⇒(x∧¬y)=x∧yx⇒(x∧¬y)⇒z=z∨¬x∨¬y(x∧y)∨(x⇒(x∧¬y)⇒z)=1
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+