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Ecuación diferencial log(x)sin(y)^3dx-xcos(y)dy=0

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
   3                  d                     
sin (y(x))*log(x) - x*--(y(x))*cos(y(x)) = 0
                      dx                    
$$- x \cos{\left(y{\left(x \right)} \right)} \frac{d}{d x} y{\left(x \right)} + \log{\left(x \right)} \sin^{3}{\left(y{\left(x \right)} \right)} = 0$$
-x*cos(y)*y' + log(x)*sin(y)^3 = 0
Respuesta [src]
                /     ______________\
                |    /     -1       |
y(x) = pi - asin|   /  ------------ |
                |  /           2    |
                \\/    C1 + log (x) /
$$y{\left(x \right)} = \pi - \operatorname{asin}{\left(\sqrt{- \frac{1}{C_{1} + \log{\left(x \right)}^{2}}} \right)}$$
                /     ______________\
                |    /     -1       |
y(x) = pi + asin|   /  ------------ |
                |  /           2    |
                \\/    C1 + log (x) /
$$y{\left(x \right)} = \operatorname{asin}{\left(\sqrt{- \frac{1}{C_{1} + \log{\left(x \right)}^{2}}} \right)} + \pi$$
            /     ______________\
            |    /     -1       |
y(x) = -asin|   /  ------------ |
            |  /           2    |
            \\/    C1 + log (x) /
$$y{\left(x \right)} = - \operatorname{asin}{\left(\sqrt{- \frac{1}{C_{1} + \log{\left(x \right)}^{2}}} \right)}$$
           /     ______________\
           |    /     -1       |
y(x) = asin|   /  ------------ |
           |  /           2    |
           \\/    C1 + log (x) /
$$y{\left(x \right)} = \operatorname{asin}{\left(\sqrt{- \frac{1}{C_{1} + \log{\left(x \right)}^{2}}} \right)}$$
Clasificación
factorable
separable
lie group
separable Integral