Sr Examen

Otras calculadoras

Ecuación diferencial dx*(-x^3+5*x*y^2)+dy*(5*x^2*y-y)=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
   3   d                    2         2 d                
- x  - --(y(x))*y(x) + 5*x*y (x) + 5*x *--(y(x))*y(x) = 0
       dx                               dx               
$$- x^{3} + 5 x^{2} y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} + 5 x y^{2}{\left(x \right)} - y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} = 0$$
-x^3 + 5*x^2*y*y' + 5*x*y^2 - y*y' = 0
Respuesta [src]
                    ___________ 
                   /        4   
          ___     /   C1 + x    
       -\/ 2 *   /   ---------  
                /            2  
              \/     -1 + 5*x   
y(x) = -------------------------
                   2            
$$y{\left(x \right)} = - \frac{\sqrt{2} \sqrt{\frac{C_{1} + x^{4}}{5 x^{2} - 1}}}{2}$$
                   ___________
                  /        4  
         ___     /   C1 + x   
       \/ 2 *   /   --------- 
               /            2 
             \/     -1 + 5*x  
y(x) = -----------------------
                  2           
$$y{\left(x \right)} = \frac{\sqrt{2} \sqrt{\frac{C_{1} + x^{4}}{5 x^{2} - 1}}}{2}$$
Clasificación
1st exact
Bernoulli
1st power series
lie group
1st exact Integral
Bernoulli Integral