Sr Examen

Ecuación diferencial dy/dx=x^2-2xy+y^2

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
d           2    2              
--(y(x)) = x  + y (x) - 2*x*y(x)
dx                              
$$\frac{d}{d x} y{\left(x \right)} = x^{2} - 2 x y{\left(x \right)} + y^{2}{\left(x \right)}$$
y' = x^2 - 2*x*y + y^2
Respuesta [src]
                     3 /        2     2 /         2\\    5 /         2     2 /        2\     2 /        2     2 /         2\       2 /         2\\       2 /         2\\                          4 /        2     2 /         2\\        
                2   x *\1 - 3*C1  + C1 *\-1 + 3*C1 //   x *\-2 + 9*C1  + C1 *\2 - 9*C1 / + C1 *\2 - 9*C1  + C1 *\-2 + 9*C1 / + 2*C1 *\-2 + 3*C1 // - 2*C1 *\-2 + 3*C1 //       2 /       2\   C1*x *\2 - 3*C1  + C1 *\-2 + 3*C1 //    / 6\
y(x) = C1 + x*C1  + --------------------------------- + ---------------------------------------------------------------------------------------------------------------- + C1*x *\-1 + C1 / + ------------------------------------ + O\x /
                                    3                                                                          15                                                                                              3                          
$$y{\left(x \right)} = \frac{x^{3} \left(C_{1}^{2} \left(3 C_{1}^{2} - 1\right) - 3 C_{1}^{2} + 1\right)}{3} + \frac{x^{5} \left(C_{1}^{2} \left(2 - 9 C_{1}^{2}\right) - 2 C_{1}^{2} \left(3 C_{1}^{2} - 2\right) + C_{1}^{2} \left(2 C_{1}^{2} \left(3 C_{1}^{2} - 2\right) + C_{1}^{2} \left(9 C_{1}^{2} - 2\right) - 9 C_{1}^{2} + 2\right) + 9 C_{1}^{2} - 2\right)}{15} + C_{1} + C_{1} x^{2} \left(C_{1}^{2} - 1\right) + \frac{C_{1} x^{4} \left(C_{1}^{2} \left(3 C_{1}^{2} - 2\right) - 3 C_{1}^{2} + 2\right)}{3} + C_{1}^{2} x + O\left(x^{6}\right)$$
Clasificación
1st power series
lie group