Ecuación diferencial sin(x)*y'+2ycos(x)x=sin(x)2x

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Ha introducido [src]

d                                             
--(y(x))*sin(x) + 2*x*cos(x)*y(x) = 2*x*sin(x)
dx

$$2 x y{\left(x \right)} \cos{\left(x \right)} + \sin{\left(x \right)} \frac{d}{d x} y{\left(x \right)} = 2 x \sin{\left(x \right)}$$

2*x*y*cos(x) + sin(x)*y' = 2*x*sin(x)

Gráfico para el problema de Cauchy

Clasificación

factorable

1st exact

1st linear

Bernoulli

almost linear

lie group

1st exact Integral

1st linear Integral

Bernoulli Integral

almost linear Integral

Respuesta numérica [src]

(x, y):

(-10.0, 0.75)

(-7.777777777777778, 1.2366981037005627e+20)

(-5.555555555555555, 2.17e-322)

(-3.333333333333333, nan)

(-1.1111111111111107, 2.78363573e-315)

(1.1111111111111107, 6.971028255580836e+173)

(3.333333333333334, 3.1933833808213398e-248)

(5.555555555555557, 6.29567287026948e-66)

(7.777777777777779, 8.388243567339305e+296)

(10.0, 3.861029683e-315)

(10.0, 3.861029683e-315)