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Ecuación diferencial xsqrt(9-y^2)dx-y(4+x^2)dy=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
     ___________                                         
    /      2         d                2 d                
x*\/  9 - y (x)  - 4*--(y(x))*y(x) - x *--(y(x))*y(x) = 0
                     dx                 dx               
$$- x^{2} y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} + x \sqrt{9 - y^{2}{\left(x \right)}} - 4 y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} = 0$$
-x^2*y*y' + x*sqrt(9 - y^2) - 4*y*y' = 0
Respuesta [src]
           ______________________________________________ 
          /         2/     2\       2           /     2\  
       -\/  36 - log \4 + x / - 4*C1  - 4*C1*log\4 + x /  
y(x) = ---------------------------------------------------
                                2                         
$$y{\left(x \right)} = - \frac{\sqrt{- 4 C_{1}^{2} - 4 C_{1} \log{\left(x^{2} + 4 \right)} - \log{\left(x^{2} + 4 \right)}^{2} + 36}}{2}$$
          ______________________________________________
         /         2/     2\       2           /     2\ 
       \/  36 - log \4 + x / - 4*C1  - 4*C1*log\4 + x / 
y(x) = -------------------------------------------------
                               2                        
$$y{\left(x \right)} = \frac{\sqrt{- 4 C_{1}^{2} - 4 C_{1} \log{\left(x^{2} + 4 \right)} - \log{\left(x^{2} + 4 \right)}^{2} + 36}}{2}$$
Clasificación
factorable
separable
1st exact
1st power series
lie group
separable Integral
1st exact Integral