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Ecuación diferencial dx*(y^2+1)=3*dy*(y2+y-3)^(x2+1)

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
     2                          x2 d                               x2 d                            x2 d            
1 + y (x) = - 9*(-3 + y2 + y(x))  *--(y(x)) + 3*y2*(-3 + y2 + y(x))  *--(y(x)) + 3*(-3 + y2 + y(x))  *--(y(x))*y(x)
                                   dx                                 dx                              dx           
$$y^{2}{\left(x \right)} + 1 = 3 y_{2} \left(y_{2} + y{\left(x \right)} - 3\right)^{x_{2}} \frac{d}{d x} y{\left(x \right)} + 3 \left(y_{2} + y{\left(x \right)} - 3\right)^{x_{2}} y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} - 9 \left(y_{2} + y{\left(x \right)} - 3\right)^{x_{2}} \frac{d}{d x} y{\left(x \right)}$$
y^2 + 1 = 3*y2*(y2 + y - 3)^x2*y' + 3*(y2 + y - 3)^x2*y*y' - 9*(y2 + y - 3)^x2*y'
Clasificación
factorable
separable
1st exact
1st power series
lie group
separable Integral
1st exact Integral