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Ecuación diferencial y''+2senx/(cosx+senx)y'-(cosx+senx)/(cosx-senx)y=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
                             d                              
                           2*--(y(x))*sin(x)     2          
  (cos(x) + sin(x))*y(x)     dx                 d           
- ---------------------- + ----------------- + ---(y(x)) = 0
     -sin(x) + cos(x)       cos(x) + sin(x)      2          
                                               dx           
$$\frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{2 \sin{\left(x \right)} \frac{d}{d x} y{\left(x \right)}}{\sin{\left(x \right)} + \cos{\left(x \right)}} - \frac{\left(\sin{\left(x \right)} + \cos{\left(x \right)}\right) y{\left(x \right)}}{- \sin{\left(x \right)} + \cos{\left(x \right)}} = 0$$
y'' + 2*sin(x)*y'/(sin(x) + cos(x)) - (sin(x) + cos(x))*y/(-sin(x) + cos(x)) = 0
Clasificación
2nd power series ordinary