cosx=c+2 la ecuación
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Solución
Solución detallada
Tenemos la ecuación
cos(x)=c+2es la ecuación trigonométrica más simple
Esta ecuación se reorganiza en
x=πn+acos(c+2)x=πn+acos(c+2)−πO
x=πn+acos(c+2)x=πn+acos(c+2)−π, donde n es cualquier número entero
x1 = -re(acos(2 + c)) + 2*pi - I*im(acos(2 + c))
x1=−re(acos(c+2))−iim(acos(c+2))+2π
x2 = I*im(acos(2 + c)) + re(acos(2 + c))
x2=re(acos(c+2))+iim(acos(c+2))
x2 = re(acos(c + 2)) + i*im(acos(c + 2))
Suma y producto de raíces
[src]
-re(acos(2 + c)) + 2*pi - I*im(acos(2 + c)) + I*im(acos(2 + c)) + re(acos(2 + c))
(re(acos(c+2))+iim(acos(c+2)))+(−re(acos(c+2))−iim(acos(c+2))+2π)
(-re(acos(2 + c)) + 2*pi - I*im(acos(2 + c)))*(I*im(acos(2 + c)) + re(acos(2 + c)))
(re(acos(c+2))+iim(acos(c+2)))(−re(acos(c+2))−iim(acos(c+2))+2π)
-(I*im(acos(2 + c)) + re(acos(2 + c)))*(-2*pi + I*im(acos(2 + c)) + re(acos(2 + c)))
−(re(acos(c+2))+iim(acos(c+2)))(re(acos(c+2))+iim(acos(c+2))−2π)
-(i*im(acos(2 + c)) + re(acos(2 + c)))*(-2*pi + i*im(acos(2 + c)) + re(acos(2 + c)))