Sr Examen

cosx=c+2 la ecuación

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Solución numérica:

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Solución

Ha introducido [src]
cos(x) = c + 2
$$\cos{\left(x \right)} = c + 2$$
Solución detallada
Tenemos la ecuación
$$\cos{\left(x \right)} = c + 2$$
es la ecuación trigonométrica más simple
Esta ecuación se reorganiza en
$$x = \pi n + \operatorname{acos}{\left(c + 2 \right)}$$
$$x = \pi n + \operatorname{acos}{\left(c + 2 \right)} - \pi$$
O
$$x = \pi n + \operatorname{acos}{\left(c + 2 \right)}$$
$$x = \pi n + \operatorname{acos}{\left(c + 2 \right)} - \pi$$
, donde n es cualquier número entero
Gráfica
Respuesta rápida [src]
x1 = -re(acos(2 + c)) + 2*pi - I*im(acos(2 + c))
$$x_{1} = - \operatorname{re}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} - i \operatorname{im}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} + 2 \pi$$
x2 = I*im(acos(2 + c)) + re(acos(2 + c))
$$x_{2} = \operatorname{re}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)}$$
x2 = re(acos(c + 2)) + i*im(acos(c + 2))
Suma y producto de raíces [src]
suma
-re(acos(2 + c)) + 2*pi - I*im(acos(2 + c)) + I*im(acos(2 + c)) + re(acos(2 + c))
$$\left(\operatorname{re}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)}\right) + \left(- \operatorname{re}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} - i \operatorname{im}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} + 2 \pi\right)$$
=
2*pi
$$2 \pi$$
producto
(-re(acos(2 + c)) + 2*pi - I*im(acos(2 + c)))*(I*im(acos(2 + c)) + re(acos(2 + c)))
$$\left(\operatorname{re}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)}\right) \left(- \operatorname{re}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} - i \operatorname{im}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} + 2 \pi\right)$$
=
-(I*im(acos(2 + c)) + re(acos(2 + c)))*(-2*pi + I*im(acos(2 + c)) + re(acos(2 + c)))
$$- \left(\operatorname{re}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)}\right) \left(\operatorname{re}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(c + 2 \right)}\right)} - 2 \pi\right)$$
-(i*im(acos(2 + c)) + re(acos(2 + c)))*(-2*pi + i*im(acos(2 + c)) + re(acos(2 + c)))